Phys 4, Section
2
Feb 20, 2002
Magnetic Field of a Moving Charge
Experiments show that the magnetic field of of moving charge can be expressed
as:

μ o ≡ 4π ×
10-7 N·s2/C2 is called the permeability
of free space. The constant εo
that is used in electric field calculations is called the permittivity of
free space. Note that εoμo
= 1/c2.
Example:
Two protons with a vertical displacement of r between them move in the
x-y plane parallel to the x-axis at the same speed v (small compared to c).
When they are both at x = 0, what is the ratio of the electric/magnetic
forces between them?
FE = kq2/r2
To get FB acting on top charge, first find B caused by bottom
charge:

So, the force this field exerts on the top charge is:

Comparing the ratio of FB to FE:

Last modified on February 27, 2002
|